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		Why triangles are better than squares 
		 By MUNGAI KIHANYA 
		The Sunday Nation 
		Nairobi, 
		15 November 2015 
		  
		
		After reading last week’s column where, Michael Wang’ombe asked me to 
		help him understand how a large hall can accommodate so many more pupils 
		in a triangular grid than in a square one. I will not go over the 
		detailed geometry as that was explained in the last article. 
		
		Last week we saw that a classroom measuring 18ft by 24 ft can fit 35 
		students in a square grid and 36 in a triangular pattern. That was just 
		one extra student or 3 per cent.  
		
		Suppose it was a hall measuring 36ft by 48ft: how many candidates would 
		fit? We will use the same limitations we had last week – minimum of 4ft 
		between candidates and one foot from the wall. 
		
		In a square grid arrangement, we get 9 pupils along the 36ft width and 
		12 along the 48ft length. This makes a total of 108 students.  
		
		For the triangular pattern, we get 14 rows; seven with 9 students and 
		the other seven with 8. The total comes to 119. That is, we fit an 
		additional 11 pupils or about 10 per cent more. 
		
		Now, the triangular pattern has a hidden advantage: the back-to-front 
		distance is a lot more. For any candidates are in a square grid, the 
		distance from one student to another on in front or behind is 4ft.  
		
		In the triangular pattern, the side-to-side separation is also 4ft but 
		the back-to-front separation is almost 7ft (6.93ft)! The reason for this 
		is the staggered arrangement of the rows. I believe this makes it more 
		difficult to cheat in the exam. 
		
		Perhaps the question that Wang’ombe did not ask is why the triangles fit 
		more students than the squares. There are two ways to explain this. 
		First is the number of nearest neighbours a candidate has in each 
		pattern. (By the way “nearest neighbour” is a proper technical term in 
		the science of crystallography) 
		
		In both patters, the nearest neighbour is 4ft away. In the square 
		pattern, a student in the middle part of the hall will have four nearest 
		neighbours. What about in the triangular arrangement? One might expect 
		that a similarly positioned pupil in the triangular arrangement would 
		have three nearest neighbours – after all, a triangle has three corners. 
		
		That is not the case at all! If you sketch the triangular grid, you will 
		find that a pupil in the middle part has six nearest neighbours. 
		Therefore, this pattern packs the candidates more tightly even though 
		they are still 4ft apart. 
		
		The second way of understanding the phenomenon is to look at the area 
		reserved for each student. A 4ft-by-4ft square has 16 square feet and 
		four students. That is, each student takes 4sq.ft. 
		
		The area of a 4ft triangle is about 7 square feet. This will have three 
		pupils – one each at the corners. Therefore, the area per student is 
		2.3sq.ft. Clearly, there is better utilisation of space in this case. 
		
		And you thought Pythagoras Theorem was a waste of time! 
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