Why triangles are better than squares
By MUNGAI KIHANYA
The Sunday Nation
Nairobi,
15 November 2015
After reading last week’s column where, Michael Wang’ombe asked me to
help him understand how a large hall can accommodate so many more pupils
in a triangular grid than in a square one. I will not go over the
detailed geometry as that was explained in the last article.
Last week we saw that a classroom measuring 18ft by 24 ft can fit 35
students in a square grid and 36 in a triangular pattern. That was just
one extra student or 3 per cent.
Suppose it was a hall measuring 36ft by 48ft: how many candidates would
fit? We will use the same limitations we had last week – minimum of 4ft
between candidates and one foot from the wall.
In a square grid arrangement, we get 9 pupils along the 36ft width and
12 along the 48ft length. This makes a total of 108 students.
For the triangular pattern, we get 14 rows; seven with 9 students and
the other seven with 8. The total comes to 119. That is, we fit an
additional 11 pupils or about 10 per cent more.
Now, the triangular pattern has a hidden advantage: the back-to-front
distance is a lot more. For any candidates are in a square grid, the
distance from one student to another on in front or behind is 4ft.
In the triangular pattern, the side-to-side separation is also 4ft but
the back-to-front separation is almost 7ft (6.93ft)! The reason for this
is the staggered arrangement of the rows. I believe this makes it more
difficult to cheat in the exam.
Perhaps the question that Wang’ombe did not ask is why the triangles fit
more students than the squares. There are two ways to explain this.
First is the number of nearest neighbours a candidate has in each
pattern. (By the way “nearest neighbour” is a proper technical term in
the science of crystallography)
In both patters, the nearest neighbour is 4ft away. In the square
pattern, a student in the middle part of the hall will have four nearest
neighbours. What about in the triangular arrangement? One might expect
that a similarly positioned pupil in the triangular arrangement would
have three nearest neighbours – after all, a triangle has three corners.
That is not the case at all! If you sketch the triangular grid, you will
find that a pupil in the middle part has six nearest neighbours.
Therefore, this pattern packs the candidates more tightly even though
they are still 4ft apart.
The second way of understanding the phenomenon is to look at the area
reserved for each student. A 4ft-by-4ft square has 16 square feet and
four students. That is, each student takes 4sq.ft.
The area of a 4ft triangle is about 7 square feet. This will have three
pupils – one each at the corners. Therefore, the area per student is
2.3sq.ft. Clearly, there is better utilisation of space in this case.
And you thought Pythagoras Theorem was a waste of time!
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