| 
		What is the benefit of planting trees in triangles?  By MUNGAI KIHANYA The Sunday Nation Nairobi, 10 November 2013   
		Three years ago (July 2010), I suggested in this column that farmers can 
		improve the yield from their land by simply changing the planting 
		pattern from the common square grid to a triangular one. I used the 
		example of cabbages and demonstrated that the triangular pattern 
		accommodates about 16 per cent more plants. 
		Now Michael Chege has pulled that article from his archives and is 
		trying to figure out “how this triangular business can be applied when 
		the normal pattern is rectangular”.  
		He writes: “I want to plant trees on my farm and I have been advised 
		space them by 1m in a row and the rows to be 2m apart. How can I convert 
		this into a triangular patter and how many extra trees can I get?” 
		Chege, let’s do the analysis on one hectare of land, that is, a piece 
		measuring 100m by 100m. If you use the rectangular pattern, you will fit 
		100 trees per row (spaced by 1m) and a total of 50 rows (rows are 2m 
		apart). That makes a total of 5,000 trees. 
		To change the pattern to triangles, you start by planting the first row 
		of 100 trees, 1m apart. The second row trees are shifted so that they 
		are aligned with the midpoints of those in the first row. 
		The second row is then brought closer to the first so that the distance 
		between its trees and those in the first is the recommended 2m. The 
		result will be trees forming isosceles triangles with two sides of 2m 
		and the third being 1m. But the second row will now have 99 trees 
		instead of 100. This pattern is repeated throughout the one hectare. 
		The next question then is: what it the distance between the rows? The 
		answer is that it is equal to the height of the triangles. A little 
		trigonometry reveals that the rows are 1.94m apart (compare that to the 
		2m in a rectangular pattern). 
		Next we find out how many rows will fit in the 100m width of the plot. 
		This comes to 51. Thus there will be 26 rows of 100 trees and 25 rows of 
		99. The total number trees come to 5,075. The question for Chege then is 
		whether 75 extra trees are worth the triangular troubles. |